SOLUTION: Please Help! I need to divide this but I am stuck! (28b^3+27b^2+26b+53)/(4b+5)

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Question 333762: Please Help! I need to divide this but I am stuck!
(28b^3+27b^2+26b+53)/(4b+5)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(28b^3+27b^2+26b+53)/(4b+5)
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4b+5 = 4(b+(5/4)
Using synthetic division to divide by (b+5/4):
-5/4)....28....27....26....53
..........28....-8....36...|..8
Quotient: 28b^2-8b+36
Remainder 8
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Divide by 4 to get proper factored form:
Quotient: 7b^2-2b+9
Remainder: 8
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Cheers,
Stan H.
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