SOLUTION: e^lnx+lny=x+y. I believe this to be true but I am not sure. Am I right?

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Question 33368: e^lnx+lny=x+y. I believe this to be true but I am not sure. Am I right?
Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
e^(lnx+lny) = (e^lnx)(e^lny) = xy (which is not x+y)