SOLUTION: log(10x/y)=1+log x-log y. I have no idea whether this problem is true or false. Could you please help show me the steps in finding the answer?
Question 33366: log(10x/y)=1+log x-log y. I have no idea whether this problem is true or false. Could you please help show me the steps in finding the answer? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! You need to know the Laws of logarithms.
log(10x/y)= log(10x)-logy
=log10+logx-logy
=1+logx-logy
Cheers,
Stan H.