Question 333647: A lot has the shape of a right triangle with one leg 2m longer than the other. The hypotenuse is 2m less than twice the length of the shorter leg. Finf the length of the shorter leg. I have tried to solve this but i can't.
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! We basically have this triangle set up:
Remember, the Pythagorean Theorem is where "a" and "b" are the legs of a triangle and "c" is the hypotenuse.
Since the legs are and this means that and
Also, since the hypotenuse is , this means that .
Start with the Pythagorean theorem.
Plug in , , and
FOIL
Get every term to the left side.
Combine like terms.
Notice that the quadratic is in the form of where , , and
Let's use the quadratic formula to solve for "x":
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the possible solutions are or
Since a length of 0 doesn't make much sense, the only solution is
So the legs of the triangle are 6 m and 8 m (add 2) while the hypotenuse is 10 m (double 6 and subtract 2)
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