SOLUTION: Solve (v-4)^2-48=0 where v is a real number. Simplify your answer as much as possible.

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Question 333645: Solve (v-4)^2-48=0 where v is a real number. Simplify your answer as much as possible.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%28v-4%29%5E2-48=0 Start with the given equation.


%28v-4%29%5E2=0%2B48Add 48 to both sides.


%28v-4%29%5E2=48 Combine like terms.


x-4=%22%22%2B-sqrt%2848%29 Take the square root of both sides.


v-4=sqrt%2848%29 or v-4=-sqrt%2848%29 Break up the "plus/minus" to form two equations.


v-4=4%2Asqrt%283%29 or v-4=-4%2Asqrt%283%29 Simplify the square root.


v=4%2B4%2Asqrt%283%29 or v=4-4%2Asqrt%283%29 Add 4 to both sides.


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Answer:


So the solutions are v=4%2B4%2Asqrt%283%29 or v=4-4%2Asqrt%283%29.