SOLUTION: How do I solve this problem? 2x^2-3x+1=0
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Question 33352
:
How do I solve this problem?
2x^2-3x+1=0
Answer by
sarah_adam(201)
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2
-3x+1=0
2
-2x-x+1=0
2x(x-1)-1(x-1)=0
(2x-1)(x-1) = 0
(2x-1)=0 or (x-1) = 0
2x = 1 or x =1
x = 1/2 or x = 1