Question 333450: The graph of y=-11x^2+154x-535 is a parabola that opens in the direction____. It has vertex____, y-intercept___, and real roots.
1. up,(7,4), 154,2
2. down,(7,4),-535,2
3. down,(7,4),-535,1
4. down,(-7,4),154,1
5.None of the above
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The graph of y=-11x^2+154x-535 is
a parabola that opens in the direction down_.
It has vertex ?,
vertex at x = -b/2a = -154/(2*-11) = 7
f(7) = 4
So, vertex at (7,4)
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y-intercept ?,
y-intercept = -535
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and real roots, ?
b^2-4ac = 154^2-4*-11*-535 = 176
Since the discriminant is positive
there are 2 Real Number roots.
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1. up,(7,4), 154,2
2. down,(7,4),-535,2
3. down,(7,4),-535,1
4. down,(-7,4),154,1
5.None of the above
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Cheers,
Stan H.
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