SOLUTION: An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic
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Question 333448: An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h = -16t^2 + 48t + 160. When will the object hit the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h = -16t^2 + 48t + 160. When will the object hit the ground?
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When h = 0
h = -16t^2 + 48t + 160 = 0
Solve for t
