Question 333392: I am attempting to solve the problem:
4x/3+6/4+(3x-2)/2
I have attempted to solve it below, but get stuck pretty quick...
4x/3+6/4+(3x-2)/2 -----> from the original problem i think you must use GCF on 6/4 which would change it to 3/2
4x/3+3/2+(3x-2)/2 -----> from here i am not sure wether to factor out the -2/2 or if i need to solve it as a quadriatic.... then from there find the LCD....
If somone could help I would be very greatful
Thank you in advance
Becca
Found 3 solutions by unlockmath, stanbon, solver91311:
Answer by unlockmath(1688)   (Show Source):
You can put this solution on YOUR website! Hello,
The key to fractions is getting the denominators all the same and then adding.
4x/3+6/4+(3x-2)/2
First reduce 6/4 to 3/2
Let's set the denominator at 6 so:
8x/6+9/6+3(3x-2)/6
Now we can rewrite this to get:
(8x+9+9x-6)/6
Combine like terms in the numerator to get:
(17x+3)/6 (note: Quadratic deals only when we have x to the 2nd power, x^2)
Make sense?
RJ
www.math-unlock.com
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! solve the problem:
4x/3+6/4+(3x-2)/2
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You do not have an equation, so there is no "solution".
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The least common denominator is 12.
Convert each fraction, as follows:
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(4*4x)/12 + (3*6)/12 + (6(3x-2))/12
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Combine the numerators over the lcd:
(16x+18+18x-12)/12
-----
(34x+6)/12
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Reduce:
(17x+3)/6
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Cheers,
Stan H.
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Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
I think you are trying to say:
But that raises the issue of what you mean by "solve." Solve, in its ordinary sense means to find a solution set for an equation or an inequality. You have neither, and so you can't actually "solve" this. Now, if you made a little typo and that plus sign between the last two terms was supposed to be an equals sign, then that is another story, but I can only go on what you actually wrote.
Be that as it may, you can simplify your expression.
Your first step was a correct one, so let's go there first:
The LCM of 2 and 3 is 6, so we choose 6 for a common denominator.
Write back if I'm right about that possible typo.
John
My calculator said it, I believe it, that settles it
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