SOLUTION: Suppose a survey of 890 families with 5 children was done.
a. what is the probability of observing children to be all boys or all girls?
b. what is the expected number of famil
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-> SOLUTION: Suppose a survey of 890 families with 5 children was done.
a. what is the probability of observing children to be all boys or all girls?
b. what is the expected number of famil
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Question 333340: Suppose a survey of 890 families with 5 children was done.
a. what is the probability of observing children to be all boys or all girls?
b. what is the expected number of families having 3 boys and 2 girls? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose a survey of 890 families with 5 children was done.
a. what is the probability of observing children to be all boys or all girls?
P(all are boys) = (1/2)^890
P(all are girls) = (1/2)^890
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P(are are boys OR all are girs) = 2*(1/2)^890 = (1/2)^889
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b. what is the expected number of families having 3 boys and 2 girls?
P(2 girls in fam. of 5) = 5C2*(1/2)^2*(1/2)^3 = 10*(1/32) = 5/16
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Cheers,
Stan H.
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