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Question 333185: The sum of three consecutive odd integers is 35 more than twice the largest. Find them.
Answer by tinbar(133)   (Show Source):
You can put this solution on YOUR website! let x represent the first odd integer. it follows then that the second ODD integer would be x+2 (note: x+1 represents the integer consecutive to x, however if x is odd, x+1 would be even, which does not fit our condition). finally, the last (largest) integer can be represented by (x+2)+2 = x+4
the question states:
the sum of 3 con...integers = 35 more(+) twice the largest (x+4)
..in math terms...
x+(x+2)+(x+4)=35+(2*(x+4))
now we solve this equation
3x+6=35+2x+8
3x-2x=35+8-6
x=37
let's check: 37, 39, and 41
firstly 37+39+41=117
secondly, 35 more than twice the largest value yields 35+ (41*2)=117
our solution works!
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