SOLUTION: Please help me write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8. please and thank you

Algebra ->  Equations -> SOLUTION: Please help me write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8. please and thank you      Log On


   

Question 333064: Please help me write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8.
please and thank you
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8.
:
Find the slope by putting the equation into the slope/intercept form (y=mx+b)
3x - 2y = 8
-2y = -3x + 8
y has to be positive, multiply by -1
2y = 3x - 8
divide both sides by 2
y = 3%2F2%29%29%29x+-+%7B%7B%7B8%2F2
y = 3%2F2x - 4
Slope: m1 = 3%2F2
;
slope relationship of the slopes of perpendicular lines is m1*m2 = -1
find m2
3%2F2*m2 = -1
m2 = -1 * 2%2F3
m2 = -2%2F3 is the slope of the perpendicular line
:
Find the equation using the point/slope form: y - y1 = m(x - x1)
m = -2%2F3, x1 = -4, y1 = 6
y - 6 = -2%2F3(x - (-4))
y - 6 = -2%2F3(x + 4)
y - 6 = -2%2F3x + (-2/3)*4
y - 6 = -2%2F3x - 8%2F3
y = -2%2F3x - 8%2F3 + 6
y = -2%2F3x - 8%2F3 + 18%2F3
y = -2%2F3x + 10%2F3 is the equation of the perpendicular line
:
:
Check by finding y when x = -4
y = -2%2F3(-4) + 10%2F3
y = 8%2F3 + 10%2F3
y = 18%2F3
y = 6