SOLUTION: In one-way ANOVA, suppose that there are five treatments with n1 = n2 = n3 = 5, and n4 = n5 = 7. Then the mean square for error, MSE, equals
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-> SOLUTION: In one-way ANOVA, suppose that there are five treatments with n1 = n2 = n3 = 5, and n4 = n5 = 7. Then the mean square for error, MSE, equals
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Question 333025: In one-way ANOVA, suppose that there are five treatments with n1 = n2 = n3 = 5, and n4 = n5 = 7. Then the mean square for error, MSE, equals Answer by jrfrunner(365) (Show Source):
You can put this solution on YOUR website! you dont have enough information to determine MSE, because MSE=SSE/dof, and you dont provide data on SSE or to be able to calculated.
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Now, if you are asking about the degrees of freedom for MSE, that can be determine with what you are providing
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Let N= total sample size =
let k= number of treatments =5
The degrees of freedom for computing MSE: N-k-1=29-5-1=23
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there is one restriction for estimating the overall mean, and one restriction for estimating each treatment mean
