SOLUTION: Find three consecutive odd integers such that 4 less than twice the second has the same value as three times the number that is one more than the third. Can someone please show

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Question 332907: Find three consecutive odd integers such that 4 less than twice the second has the same value as three times the number that is one more than the third.
Can someone please show me how to solve this?
Found 2 solutions by benazir.sj@gmail.com, checkley77:
Answer by benazir.sj@gmail.com(109) (Show Source):
You can put this solution on YOUR website!

solution:
Variables
x = first consecutive odd integer
x + 2 = second consecutive odd integer
x + 4 = third consecutive odd integer
HINT: Break them up into smaller pieces if you're having trouble.
Given: 4 less
Means: - 4
Given: than twice the second
Means: 2 * (x + 2) = 2(x + 2)
Given: has the same value as
Means: =
Given: three times
Means: 3 *
Given: the number that is one more than third
Means: 1 + x + 4 =
Put them all back together.
Given: 4 less than twice the second has the same value as three times the number that is one more than third.
Means: 2(x + 2) - 4 = 3(1 + x + 4)
Simplify.
2(x + 2) - 4 = 3(x + 5)
Distribute.
2(x) + 2(2) - 4 = 3(x) + 3(5)
2x + 4 - 4 = 3x + 15
2x = 3x + 15
Subtract 3x from both sides.
2x - 3x = 3x + 15 - 3x
-x = 15
Divide both sides by -1.
-x / -1 = 15 / -1
x = -15
Plug this solved value into the variables.
x = first consecutive odd integer = -15
x + 2 = second consecutive odd integer = -15 + 2 = -13
x + 4 = third consecutive odd integer = -15 + 4 = -11
ANSWER: The 3 numbers are -15, -13, and -11

Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
Let x, x+2, x+4 be the 3 integers.
2(x+2)-4=3(x+4+1)
2x+4-4=3(x+5)
2x=3x+15
-x=15
x=-15 ans for the smallest integer.
-15+2=-13 for the second integer.
-15+4=-11 for the third integer.
Proof:
2*-13-4=3(-11+1)
-26-4=3*-10
-26-4=-30
-30=-30