SOLUTION: [(-2x to 5th power y to the 2nd power) 2nd power] 3rd power
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Question 332638
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[(-2x to 5th power y to the 2nd power) 2nd power] 3rd power
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benazir.sj@gmail.com(109)
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[(-2x^5y^2)^2]^3
[-2^2x^5*2 y^2*2]^3
[-4x^10y^4]^3
[-4^3 x^10*3 y^4*3]
[-64x^30y^12]
-64x^30y^12 is the answer