SOLUTION: The sum of the smaller of two consecutive integers and twice the larger integer is 47. What are the integers?
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Question 332552
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The sum of the smaller of two consecutive integers and twice the larger integer is 47. What are the integers?
Answer by
checkley77(12844)
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X+2(X+1)=47
X+2X+2=47
3X=47-2
3X=45
X=45/3
X=15 ANS.FOR THE SMALLER INTERGER.
15+1=16 ANS. FOR THE LARGER INTEGER.
PROOF:
15+2*16=47
15+32=47
47=47