SOLUTION: The following is my problem:
A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have. I know this looks simple but I cannot figure it
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A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have. I know this looks simple but I cannot figure it
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Question 33249: The following is my problem:
A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have. I know this looks simple but I cannot figure it out. I keep getting a negative number. Please help! Answer by sarah_adam(201) (Show Source):
You can put this solution on YOUR website! Let number of Nickels be N
and Number of dimes be D
given 0.05(D)+ 0.10(N) = 1.15
ALso given N = 2+D
so (5/100)D +(10/100)N = 1.15
5D + 10N = 115
substitute the value of N
5D + 10(2+D) = 115
5D + 20 +10D = 115
15D = 105
D = 7
N = 7+2 = 9
THerfore Number of Dimes = 7
Number of Nickels = 2
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