SOLUTION: If one side of a square is increased by 8 cm and an adjacent side is decreased by 2 cm, a rectangle is formed whose perimeter is 40 cm. Find the length of a side of the original sq

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Question 332039: If one side of a square is increased by 8 cm and an adjacent side is decreased by 2 cm, a rectangle is formed whose perimeter is 40 cm. Find the length of a side of the original square.
Answer by jrfrunner(365) About Me  (Show Source):
You can put this solution on YOUR website!
x= side of original square
rectangle formed Length=x+8, Width=x-2
Perimeter = 2*Length + 2Width or
Perimeter/2=Length + Width
so...
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Perimeter/2=Length + Width
40/2= (x+8)+(x-2) = 2*x+6
20-6 = 2x
7=x