SOLUTION: please help Suppose that you invest $3,000 into an account that pays 4.3% interest compounded continuously, find to the nearest tenth of a year when the account will be worth $9

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: please help Suppose that you invest $3,000 into an account that pays 4.3% interest compounded continuously, find to the nearest tenth of a year when the account will be worth $9      Log On


   



Question 331898: please help
Suppose that you invest $3,000 into an account that pays 4.3% interest compounded continuously, find to the nearest tenth of a year when the account will be worth $9,000.
thanks

Answer by jrfrunner(365) About Me  (Show Source):
You can put this solution on YOUR website!
F=Future value
r=annual interest rate
t= number of years
I=Initial investment
======
The formula for continuously compounded value is
F=I%2Ae%5E%28rt%29
given F=9000, I=3000, r=4.3%, t=unknown
9000=3000e%5E%280.043%2At%29 solve for t
ln(9000/3000)=0.043*t
ln(3)/0.043=t
can you finish this?