SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 80 mph and train b is traveling 100 mph. Train A passes a station at 6:15 am. If train B
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Question 331763: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 80 mph and train b is traveling 100 mph. Train A passes a station at 6:15 am. If train B passes the same station at 6:27 am, at what time will train B catch up to train A? Found 2 solutions by mananth, mathmandotcom:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
train B passes the station after 12 minutes
Train A speed is 80mph
so in 12 minutes Train A travels 12/60 *80
=16 miles.
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train B speed = 100 mph. Train A speed speed 80 mph
so it catches up 20 miles per hour ( 100-80)
20 miles it catches up in 1 hour
16 miles it will catch up in ?
16/20 hours
4/5 hours.
4/5 * 60 minutes
=48 minutes.
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Train B passes the station at 6.27 am
add 48 minutes to 6.27 am
it catches up at 7.15 am
You can put this solution on YOUR website! The solution to this problem lies in the equation d=rt
d=distance; da=distance train a travels, db=distance train b travels
r=rate; ra=80, rb=100
t=time; ta= time for train a, tb=time for train b
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da=db so ta*ra=tb*rb train A has a head start by 12 minutes or 80*12/60=16m
da=16+80t=100t=db
16+80t=100t subtract 80t
16=20t divide by 20
4/5=t in hours in minutes 4/5*60=48minutes; answer
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