SOLUTION: please solve the equation that is reducible to a quadratic equation. {{{2t/(t-3)-1/(t+4)=1}}}

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Question 331592: please solve the equation that is reducible to a quadratic equation.
2t%2F%28t-3%29-1%2F%28t%2B4%29=1
Answer by texttutoring(324) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply everything by (t-3), then multiply everything by (t+4). This will eliminate the denominators and reduce the equation to:

2t(t+4) - (t-3) = (t+4)(t-3)

Expand and distribute:

2t^2 +8t -t + 3 = t^2 -3t +4t -12

Now collect like terms:
t^2 + 6t + 15 = 0

Use the quadratic equation to solve this.

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

You should find that there are two complex solutions:
x = -3 - i*sqrt(6)
x = -3 + i*sqrt(6)

Are you familiar with complex solutions? If you're confused, let me know. Hope this helps!