Question 331366: Flying against the wind, an airplane travels 5580 in 9 hours. Flying with the wind, the same plane travels 4200 in 5 hours. What is the rate of the plane in still air and what is the rate of the wind?
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Flying against the wind, an airplane travels 5580 in 9 hours. Flying with the wind, the same plane travels 4200 in 5 hours. What is the rate of the plane in still air and what is the rate of the wind?
------------------
5580 what? Furlongs? Miles? Nautical miles?
I'll assume nautical miles, since that's what aircraft use.
5580/9 = 620 knots
4200/5 = 840 knots
The airspeed is the average (620+840)/2 = 730 knots
The "speed in still air" is called the airspeed.
If the people writing the textbooks don't know that, they should not enter problems dealing with it.
-----------------------
The wind speed is the difference between airspeed and ground speed
= 840 - 730
= 110 knots
-------------
Aircraft use knots, not mph, for speeds, and so do the weather forecasters.
1 knot = 1 nautical mile per hour
Answer by solver91311(24713)  (Show Source):
|
|
|
