SOLUTION: I looked to see if any questions were like mine, I found one or two, but they had so much more information in them and it was a little confusing. So here is my question Thank You!

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Question 33132: I looked to see if any questions were like mine, I found one or two, but they had so much more information in them and it was a little confusing. So here is my question Thank You!
Question:
Dave Invested $17,000, part at 18% and part at 4%. If the total interest at the end of the year is $1,380, how much did he invest at each rate.
Thank You,
Trinia

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let's assume that Dave invested $x at 18% and the remainder ($17,000 - $x) at 4%.
The interest earned on the $x is: 18% of x
The interest earned on the remainder ($17,000 - $x) is: 4% of ($17,000 - $x).
The sum of these two amounts is: $1,380
So, if you change the percents to their decimal equivalents, you can write the equation which can then be solved for x.
0.18x+%2B+0.04%2817000-x%29+=+1380 Simplify and solve for x.
0.18x+%2B+680+-+0.04x+=+1380 Combine like-terms.
0.14x+%2B+680+=+1380 Subtract 680 from both sides of the equation.
0.14x+=+700 Divide both sides by 0.14
x+=+5000
Dave invested $5,000 at 18% interest and ($17,000 - $5,000) $ 12,000 at 4% interest.