Question 33130: Annilee's present age is 2/3 of Jessie's present age. In 8 years the sum of their ages will be 61 years. Find their present ages. Found 2 solutions by sarah_adam, priya:Answer by sarah_adam(201) (Show Source):
You can put this solution on YOUR website! Let the present age of Jessie be x
therfore Annilee's present age is (2/3)x
eight years from now Annilee's present age will be(2/3)x+8
and age of Jessie will be x+8
given sum of their ages after 8 years will be 61
therfore
(2/3)x+8 + (x+8) = 61
(2/3)x+x = 61 - 16 = 45
5x=135
x = 27
therfore Jessie present age is 27 years
and Annilee's present age is 2/3 *27 = 18 years
You can put this solution on YOUR website! First try to form equation with the informations given in the question.
let A be Annilee's present age and J be Jessie's present age.
so eq 1. A = 2/3 (J) (PRESENT AGE)
eq 2. In 8 yrs ,sum of the 2 girls ages = 61,that is written as
(A +8) + (J + 8) = 61.(AFTER 8 YEARS)
SIMPLIFYING this we get,
A + J + 16 =61
A + J = 61-16
this is the NEW eq 2. A + J = 45
SUSTITUTE THE VALUE OF A as "2/3 (J)" in NEW eq 2 (from eq1).
therefore the NEW eq 2. becomes,
(2/3)*J + J =45
(2J +3J )/3 = 45
5J = 45 *3
THEREFORE J = 135/5
= 27 .
if J = 27, A = 2/3(27)( from eq.1)
= 18.
Jessie's age is 27 years and Annilee's age is 18 years..
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