Question 33126: In a right triangle, angle A = 41 degrees and a = 20 in.; find c to the nearest hundredth.
Answer by kietra(57)   (Show Source):
You can put this solution on YOUR website! For this problem, you'll have to use this sine rule.
Sine rule is this: a/sinA=b/sinB=c/sinC. You can pick whichever sides to use you would like.
So in this problem, use a/sinA, or 20/sin41 and then use your right angle and the side opposite the right angle- usually c.
20/sin41=c/sin90
30.49=c/1
30.49=c
|
|
|
