SOLUTION: the petty-cash drawer of a small office containing $16.25. If there were twice as many nickels as quarters and as many dimes as nickels and quarters combined, how many coins of eac

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the petty-cash drawer of a small office containing $16.25. If there were twice as many nickels as quarters and as many dimes as nickels and quarters combined, how many coins of eac      Log On


   

Question 331155: the petty-cash drawer of a small office containing $16.25. If there were twice as many nickels as quarters and as many dimes as nickels and quarters combined, how many coins of each type were there?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let quarters be x
nickels =2x
dimes = (2x+x)
..
Total money = 16.25
25x +5*2x+10*(2x+x)=1625
25x+10x+20x+10x=1625
65x=1625
x= 1625/65
x= 25 the number of quarters
nickels = 2x = 2*25=50
dimes = 3x=3*25=75