SOLUTION: Three times the greatest of three consecutive even integers exceeds twice the least by 38. Find the integers.

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Question 331065: Three times the greatest of three consecutive even integers exceeds twice the least by 38. Find the integers.
Answer by neatmath(302) About Me  (Show Source):
You can put this solution on YOUR website!

Three consecutive even integers are

x, x+2, x+4

3%2A%28x%2B4%29=%282%2Ax%29%2B38 given

3x%2B12=2x%2B38 distribute

x=26 simplify

Thus, the 3 even integers are 26, 28, and 30.

I hope this helps!