Question 33105: 1)There are two bags A and B.
A has tickets numbered 1,2,3,4,5,6,7,8,9
B has tickets numbered 1,2,3,4,5
A ticket is drawn randomly from one of the two bags.
If the ticket number is odd then the next ticket is drawn from the other bag.
If the ticket number is even then the next ticket is drawn from the same bag.
What is the probability that both tickets will be numbered even?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! P(even,even)= P(even/even|A) + P(even/even|B)
P(even,even|A) = [P(EE and A)]/P(A) =[(4/9)(3/8)]/(1/2)= 1/3
P(even,even|B) = [P(EE and B)]/P(B) =[(2/5)(1/4)]/(1/2)= 1/5
So, P(EE) = 1/3 + 1/5 = 8/15
Comment: I am not 100% confident this is the correct approach
but it is my best shot at it.
Cheers,
Stan H.
|
|
|
