SOLUTION: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?

Algebra ->  Graphs -> SOLUTION: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?       Log On


   

Question 33090: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?


Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the formula for the perimeter of a rectangle.
P+=+2%28L%2BW%29 But L = W+4 and P = 4254 feet, so:
424+=+2%28W%2B4%2BW%29
424+=+2%284%2B2W%29
424+=+8%2B4W Subtract 8 from both sides of the equation.
416+=+4W Divide both sides by 4.
104+=+Wfeet and
L+=+W%2B4
L+=+104+%2B+4
L+=+108feet