SOLUTION: Solve the system of equations: y = x^2 - 4^x + 4 and y = -x^2 + 6x - 8

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Question 330858: Solve the system of equations:
y = x^2 - 4^x + 4 and y = -x^2 + 6x - 8
Found 2 solutions by privani, Fombitz:
Answer by privani(34) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming Q1 is: y=x%5E2-4x%2B4,
using equation rule: %28a-b%29%5E2=a%5E2-2ab%2Bb%5E2,
y=x%5E2-4x%2B4
y = (x-2)(x-2)
Q2:
y=-x%5E2%2B6x-8
y=(-x+4)(x-2)

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+-4x+%2B+4=+-x%5E2+%2B+6x+-+8
2x%5E2-10x%2B12=0
x%5E2-5x%2B6=0
%28x-2%29%28x-3%29=0
Two solutions:
x-2=0
x=2
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x-3=0
x=3
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Now use either equation to solve for y.
x=2,y=2%5E2-4%282%29%2B4=0:(2,0)
x=3,y=3%5E2-4%283%29%2B4=1:(3,1)
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