Question 330449: Hello, I was hoping you'd please help me out with a math problem.
I have to find an equation in standard form of the line:
a. through (2,-2) and (4,4)
b. perpendicular to y= x + 5 and through (0, -8)
Can you please show me how to solve this problem?
Thank you so much for your help!
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! I have to find an equation in standard form of the line:
a. through (2,-2) and (4,4)
slope between points = y2-y1 / x2-x1
=4-(-2)/4-2
=6/2
=3 = slope
the general equation with slope 3 , y= 3x+b
(2-2) is on the line
-2=2*3+b
-2=6+b
-2-6=b
b=-8
So the equation will be y = 3x-8
b. perpendicular to y= x + 5 and through (0, -8)
y= x+5
compare with y = mx+b
m=1 slope
the line passes through (0,-8)& perpendicular to y =x+5
so the slope of this line will be -1
to find b plug the value of (0,8) & m
8=0+b
b=8
The equation of this line with slope -1 and b = 8 will be
y=-x+8
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