Question 330398: I am completely lost trying to figure out these tables! I would love some help trying to figure it out!! Thanks!
The frequency distribution shown lists the number of hours per day a randomly selected sample of teenagers spent watching television.
Hours per day # of teens = f Midpoint = x Fx Fx²
0 ≤ x < 1 18
1 ≤ x < 2 31
2 ≤ x < 3 24
3 ≤ x < 4 38
4 ≤ x < 5 27
5 ≤ x < 6 12
6 ≤ x < 7 15
a. Complete the table.
b. Construct a histogram representing the data.
c. Calculate the mean, median, and mode number of hours the teens watch television.
d. Calculate the standard deviation.
e. What percent of the data lies within one standard deviation of the mean?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I am completely lost trying to figure out these tables! I would love some help trying to figure it out!! Thanks!
The frequency distribution shown lists the number of hours per day a randomly selected sample of teenagers spent watching television.
Hours per day # of teens = f Midpoint = x Fx Fx²
0 ≤ x < 1 18
1 ≤ x < 2 31
2 ≤ x < 3 24
3 ≤ x < 4 38
4 ≤ x < 5 27
5 ≤ x < 6 12
6 ≤ x < 7 15
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Comment:
When you have a frequency distribution of the kind you have lost
the data because it has been sorted into bins.
You must use the "mark" of each bin as the representative
value for the bin.
So
for 0<= x <1 use (1+0)/2 = 0.5 with frequency 18
for 1<= x <2 use (2+1)/2 = 1.5 with frequency 31
Do that for each of the bins to complete the table.
a. Complete the table.
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b. Construct a histogram representing the data.
You can do that that with the original data
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c. Calculate the mean, median, and mode number of hours the teens watch television.
The mode with be x = 3.5 with frequency 38.
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d. Calculate the standard deviation.
Hopefully you have tecnology to do this.
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e. What percent of the data lies within one standard deviation of the mean?
I'll leave that to you.
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Cheers,
Stan H.
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