SOLUTION: Hello Can someone advise if this right. I hope I used the correct formula In how many ways you can randomly select 5 students from a 12-student class? ANS: 12C5 = (12*11*10*9

Algebra ->  Probability-and-statistics -> SOLUTION: Hello Can someone advise if this right. I hope I used the correct formula In how many ways you can randomly select 5 students from a 12-student class? ANS: 12C5 = (12*11*10*9      Log On


   

Question 330304: Hello Can someone advise if this right. I hope I used the correct formula
In how many ways you can randomly select 5 students from a 12-student class?
ANS: 12C5 = (12*11*10*9*8)/(1*2*3*4*5) = 792

Also Can some please advise on the bwlow item I ansewered question B but I am not the greatest with Sample Space.
Consider the probability experiment of drawing one card from a deck of cards.
a) Determine the sample space of the probability experiment.
ANS:
b) Determine the probability of randomly selecting a face (Q, J or K) card.
ANS: 12/52=.23
Found 3 solutions by Edwin McCravy, Fombitz, jim_thompson5910:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Hello Can someone advise if this right. I hope I used the correct formula
In how many ways you can randomly select 5 students from a 12-student class?
ANS: 12C5 = (12*11*10*9*8)/(1*2*3*4*5) = 792

That's correct!

Also Can some please advise on the below item I answered question B but I am not the greatest with Sample Space.
Consider the probability experiment of drawing one card from a deck of cards.
a) Determine the sample space of the probability experiment.
ANS: 


 
{A♥  2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 

A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦

A♠   2♠   3♠   4♠   5♠   6♠   7♠   8♠  9♠  10♠  J♠  Q♠  K♠
  
A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣} 

That's the sample space.  It contains 52 cards.

The probability of drawing a face card is found by counting the successful
ways to get a face card, which is these 12:


 
{J♥  Q♥  K♥ 

J♦  Q♦  K♦

J♠  Q♠  K♠
  
J♣  Q♣  K♣}

ways out of the 52 in the sample space or 12%2F52 

which reduces to 3%2F13

Edwin

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

.
.
.
Sample space would be a list of all of the posssible outcomes.
So you would list all of the cards.
(2 Club)(2 Spade)(2 Heart)(2 Diamond)
(3 Club)(3 Spade)(3 Heart)(3 Diamond)
.
.
.
.
(K Club)(K Spade)(K Heart)(K Diamond)
(A Club)(A Spade)(A Heart)(A Diamond)
8b) There are 12 face cards, there are 52 total cards.
P(face)=12%2F52=3%2F13

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If order doesn't matter, then you are correct in saying that 12 C 5 = 792


a) The sample space is just the set of all possible items that you can select. In this case, the sample space is the set of 52 cards that you can select from.

b) Correct. There are 4 suits and 3 face cards (Q, J, K). So there are 12 face cards total out of 52 cards which means that the probability is about 12/52=0.230769 or about a 23.0769% chance