Question 330250: Hi,
I'm a little confuse with this one:
(2x exponent 3 y exponent of -3 /x exponent of -2 y exponent of 3) exponent outside of parenthesis -5
(2x3y-3)outside exponent of parenthesis -5
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(x-2y3)
Pls. note the x3 = x with exponent of 3
y-3 = exponent of -3
x-2 = exponent of -2
y3 = expnonent of 3
-5 is outside of entire parenthesis.
Thanks!
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
I think you are trying to render:
^{-5})
And you didn't say, but the only thing I can think you might want is to simplify this, so:
Move negative exponent items from numerator to denominator and vice versa (leave the -5 exponent alone for the time being). The negative exponents become positive when they move, and then you just add the exponents for like variables.
^{-5})
Now remove the negative sign from the -5 exponent and invert the fraction inside the parentheses:
^{5})
Raising a power to a power, multiply the exponents:
To the extent that I rendered your problem as you intended, you should have written:
((2x^3y^(-3))/(x^(-2)y^3))^(-5).
Furthermore, next time tell us what it is that you actually want, and what is giving you trouble. This is Algebra.com, not the Psychic Hot Line.
John
My calculator said it, I believe it, that settles it
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