SOLUTION: find the center and the radius of (x+3)^2+(y-2)^2=4

Algebra ->  Equations -> SOLUTION: find the center and the radius of (x+3)^2+(y-2)^2=4      Log On


   



Question 330245: find the center and the radius of
(x+3)^2+(y-2)^2=4

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Compare to the general equation for a circle centered at (h,k) with a radius R is:
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
Comparing,
(h,k)=(-3,2)
R=2.