SOLUTION: I'm on college and math is not my subject. I have tried to work these problems, but I just can't get them. Please help me solve the Quadratic equation x2-2x-13=0 and 4x2-4x+3=0 Th

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I'm on college and math is not my subject. I have tried to work these problems, but I just can't get them. Please help me solve the Quadratic equation x2-2x-13=0 and 4x2-4x+3=0 Th      Log On


   



Question 330143: I'm on college and math is not my subject. I have tried to work these problems, but I just can't get them. Please help me solve the Quadratic equation x2-2x-13=0 and 4x2-4x+3=0 Thanks so much.
Found 2 solutions by privani, mananth:
Answer by privani(34) About Me  (Show Source):
You can put this solution on YOUR website!
Q1:
x%5E2-2x-13=0, where a=1, b=-2, c=-13.
Use Quadratic Equation:
x+=+%28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F2a
x+=+%28-%28-2%29+%2B-+sqrt%28%28-2%29%5E2-4%281%29%28-13%29%29%29%2F2%281%29
x+=+%282+%2B-+sqrt%284%2B52%29%29%2F2
x+=+%282+%2B-+sqrt+%2856%29%29%2F2
x+=+%282+%2B-+7.483%29%2F2
Therefore,
x+=+%282+%2B+7.483%29%2F2
x+=+9.483%2F2
x = 4.742
OR
x+=+%282+-+7.483%29%2F2
x+=+-5.483%2F2
x = -2.742

Q2: Please check if the question is typed correctly.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x2-2x-13=0
compare it with the general equation
ax^2 +bx +c
a=1, b=-2, c=-13
x1,x2 the roots of the equation are
x1+=+%28-b+%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
.
plug the values of a,b,c in the equation.
x1=%28-%28-2%29%2Bsqrt%28%28-2%29%5E2-4%2A1%2A%28-13%29%29%29%2F%282%2A1%29
x1=%2B2%2Bsqrt%284%2B52%29%2F%282%29
x1=+2%2Bsqrt%2856%29%2F%282%29
x1=%282%2B2%2Asqrt%2814%29%29%2F%282%29
x1=%282%2A%281%2Bsqrt%2814%29%29%29%2F2
x1=%281%2Bsqrt14%29
..
x2=+2-sqrt%2856%29%2F%282%29
x2=%282-2%2Asqrt%2814%29%29%2F%282%29
x2=%282%2A%281-sqrt%2814%29%29%29%2F2
x2=%281-sqrt14%29
..
and 4x2-4x+3=0
compare it with the general equation
ax^2 +bx +c
a=4, b=-4, c=3
x1,x2 the roots of the equation are
x1+=+%28-b+%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
.
plug the values of a,b,c in the equation.
x1=%28-%28-4%29%2Bsqrt%28%28-4%29%5E2-4%2A4%2A%283%29%29%29%2F%282%2A4%29
x1=%28%2B4%2Bsqrt%284-48%29%29%2F%288%29
x1=%282%2Bsqrt%28-11%29%29%2F4
x1=%281%2F2%29%2Bsqrt%28-11%29%2F4
x2=%281%2F2%29-sqrt%28-11%29%2F4







Thanks so much.