SOLUTION: given {{{k(x)=sqrt(x+1)}}} A.find k(-3) k(-2) k(-1) k(0) k(3) B. write the domain of k in interval notation C. construct the graph of k

Algebra ->  Rational-functions -> SOLUTION: given {{{k(x)=sqrt(x+1)}}} A.find k(-3) k(-2) k(-1) k(0) k(3) B. write the domain of k in interval notation C. construct the graph of k      Log On


   



Question 330139: given k%28x%29=sqrt%28x%2B1%29
A.find
k(-3)
k(-2)
k(-1)
k(0)
k(3)
B. write the domain of k in interval notation
C. construct the graph of k

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
k%28x%29=sqrt%28x%2B1%29
I'll do one, you do the rest.
k%28x%29=sqrt%28x%2B1%29
k%28-3%29=sqrt%28-3%2B1%29
k%28-3%29=sqrt%28-2%29
Since sqrt%28-2%29 is not defined, the answer is undefined.
.
.
.
Use the same method to get the other values unless they're undefined.
.
.
.
b) The domain is all x for which the function is defined.
The square root function requires non-negative arguments.
k%2B1%3E=0
k%3E=-1
.
.
.
(-1,infinity)
.
.
c)
.
.
.
graph%28300%2C300%2C-3%2C10%2C-6%2C6%2Csqrt%28x%2B1%29%29