SOLUTION: (6x^3-8x^2-14x+13)/(3x+2)

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Question 330084: (6x^3-8x^2-14x+13)/(3x+2)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%286x%5E3-8x%5E2-14x%2B13%29%2F%283x%2B2%29
First term: 2x%5E2
2x%5E2%283x%2B2%29=6x%5E3%2B4x%5E2
Subtract this product from the original polynomial to get the remainder,
%286x%5E3-8x%5E2-14x%2B13%29-%286x%5E3%2B4x%5E2%29=-12x%5E2-14x%2B13
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Second term:-4x
-4x%283x%2B2%29=-12x-8x
Subtract this product from the remainder to get the new remainder,
%28-12x%5E2-14x%2B13%29-%28-12x-8x%29=-6x%2B13
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Third term:-2
-2%283x%2B2%29=-6x-4
Subtract this product from the remainder to get the new remainder,
%28-6x%2B13%29-%28-6x-4%29=17
No further division is possible.
Gather all of the term and the final remainder.
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%286x%5E3-8x%5E2-14x%2B13%29%2F%283x%2B2%29=%282x%5E2-4x-2%29%2B17%2F%283x%2B2%29