SOLUTION: (y+2)/(y^2-y-2)+(y+1)/(y^2-4)=(1)/(y+1)

Algebra ->  Graphs -> SOLUTION: (y+2)/(y^2-y-2)+(y+1)/(y^2-4)=(1)/(y+1)      Log On


   

Question 33007: (y+2)/(y^2-y-2)+(y+1)/(y^2-4)=(1)/(y+1)
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!

LHS:
Take the LCM,

Factorizing,

Taking out common factor (y-2)
+%28%28y%2B2%29%5E2%2B%28y%2B1%29%5E2%29%2F%28%28y-2%29%28y%2B1%29%28y%2B2%29%29+
This equals
+%28%281%29%2F%28y%2B1%29%29+
So we get,

Cancelling (y+1)
+%28%28y%2B2%29%5E2%2B%28y%2B1%29%5E2%29%2F%28%28y-2%29%28y%2B2%29%29+=+1+
+%28%28y%2B2%29%5E2%2B%28y%2B1%29%5E2%29+=+%28%28y-2%29%28y%2B2%29%29+
Open the brackets
+2y%5E2%2B6y%2B5+=+y%5E2-4+
Take everything to one side
+y%5E2%2B6y%2B9=0
Which reduces to
+%28y%2B3%29%5E2=0
Hence,
y=-3


Hope this helps,
xC