SOLUTION: Could you help me again? For some reason the chart doesnt show here, but Im hoping you can make it out & help me solve and explain the steps along the way, so hat I may understand

Algebra ->  College  -> Linear Algebra -> SOLUTION: Could you help me again? For some reason the chart doesnt show here, but Im hoping you can make it out & help me solve and explain the steps along the way, so hat I may understand       Log On


   



Question 33004: Could you help me again? For some reason the chart doesnt show here, but Im hoping you can make it out & help me solve and explain the steps along the way, so hat I may understand it better. Thank you very much. :)
Fill in the chart given this linear equation:
3x + y = 10
x y
-2
-1
0
1
2

Dee

Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
This requires you to substitute the given values of x and solve for y:
3x + y = 10
For example:
x=-2
then we get,
3(-2)+y=10
y-6=10
y=16


 x  y
-2  16
-1  13
 0  10
 1  7
 2  4


Hope this helps,
xC