SOLUTION: The perimeter of a rectangle is 56inches. The length exceeds the width by 24 inches. Find the length and the width.
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Question 329953: The perimeter of a rectangle is 56inches. The length exceeds the width by 24 inches. Find the length and the width. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! L=W+24
P=2L+2W
56=2(W+24)+2W
56=2W+48+2W
56=4W+48
4W=56-48
4W=8
W=8/4
W=2 ANS. FOR THE WIDTH.
L=2+24=26 ANS. FOR THE LENGTH.
PROOF:
56=2*26+2*2
56=52+4
56=56
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