SOLUTION: Given a mean of 120 and a standard deviation of 5.5, find the 95th percentile.

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Question 329761: Given a mean of 120 and a standard deviation of 5.5, find the 95th percentile.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given a mean of 120 and a standard deviation of 5.5,
find the 95th percentile.
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Find the z-value with a left tail of 0.95.
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invNorm(0.95) = 1.645
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Use x = zs+u to find the 95th% score.
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x = 1.645*5.5+120 = 129.05
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Cheers,
Stan H.