SOLUTION: Keiko bicycles 5 km/h faster than Praedup. In the same time it takes praedup to bicycle 54 km, Keiko can bicycle 69 km. How fast does each bicyclist travel? Praedup travels _

Click here to see ALL problems on Expressions-with-variables

Question 329732: Keiko bicycles 5 km/h faster than Praedup. In the same time it takes praedup to bicycle 54 km, Keiko can bicycle 69 km. How fast does each bicyclist travel?
Praedup travels ______ km/h.
Keiko travels ________ km/h.

Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
Keiko bicycles 5 km/h faster than Praedup. In the same time it takes praedup to bicycle 54 km, Keiko can bicycle 69 km. How fast does each bicyclist travel?
Praedup travels ______ km/h.
Keiko travels ________ km/h.
..
let Praedup rate be x
Keiko's rate = x+5
..
time taken by Praedup = 54/x
time taken by Keiko = 69/(x+5)
54/x = 69/(x+5)
69x=54(x+5)
69x=54x+270
69x-54x=270
15x=270
x=270/15
x=18km/h ---- Praedup's rate
Keiko's rate = x+5 , = 18+5=23 km/h

SOLUTION: Keiko bicycles 5 km/h faster than Praedup. In the same time it takes praedup to bicycle 54 km, Keiko can bicycle 69 km. How fast does each bicyclist travel? Praedup travels __