SOLUTION: k3' = k3k5/ k4+k5 k1' = k1A(k3'/k3'+k2) Unsure how to substitute k3' into second equation and simplify. Please help, step by step explaination is better. Thanks

Algebra ->  College  -> Linear Algebra -> SOLUTION: k3' = k3k5/ k4+k5 k1' = k1A(k3'/k3'+k2) Unsure how to substitute k3' into second equation and simplify. Please help, step by step explaination is better. Thanks      Log On


   

Question 329671: k3' = k3k5/ k4+k5
k1' = k1A(k3'/k3'+k2)
Unsure how to substitute k3' into second equation and simplify. Please help, step by step explaination is better.
Thanks
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I hope it's OK that I change some of your variables.
B=k3
C=k3'
D=k4
E=k5
F=k1
G=k1'
H=k2
k3' = k3k5/ k4+k5
1.C=BE%2F%28D%2BE%29
k1' = k1A(k3'/k3'+k2)
2.G=FAC%2F%28C%2BH%29
Substitute eq. 1 into eq. 2,
G=%28FA%28BE%2F%28D%2BE%29%29%29%2F%28%28BE%2F%28%28D%2BE%29%2BH%29%29%29
Multiply numerator and denominator by %28D%2BE%29
G=FABE%2F%28BE%2B%28D%2BE%29H%29
G=FABE%2F%28BE%2BDH%2BEH%29
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.
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k1'=(k1*A*k3*k5)/(k3*k5+k4*k2+k5*k2)