SOLUTION: The number of tickets sold each day for an upcoming performance of handel's messiah is given by N(x)=-0.3x^2+6x+10, where x is the number of days since the concert was first announ
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-> SOLUTION: The number of tickets sold each day for an upcoming performance of handel's messiah is given by N(x)=-0.3x^2+6x+10, where x is the number of days since the concert was first announ
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Question 329394: The number of tickets sold each day for an upcoming performance of handel's messiah is given by N(x)=-0.3x^2+6x+10, where x is the number of days since the concert was first announced. When will daily ticket sales peak and how many tickets will be sold that day? Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The number of tickets sold each day for an upcoming performance of Handel's messiah is given by N(x)=-0.3x^2+6x+10, where x is the number of days since the concert was first announced. When will daily ticket sales peak and how many tickets will be sold that day?
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N(x)=-0.3x^2+6x+10
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max occurs when x = -b/2a = -6/(2*-0.3) = -6/-0.6 = 10 (max sales on day 10)
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N(10) = -0.3(10)^2+6*10+10 = 40 tickets will be sold on day 10
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Cheers,
Stan H.
You can put this solution on YOUR website! The minus sign in front of the term tells me
that the curve has a max at the top, not a min at the
bottom. What is needed is to find the point MAX(x,N)
For an equation of the form , is at . For the given equation: , so
Now I need to find
Ticket sales will peak on the 10th day and 40 tickets will be sold that day
Here's a graph of equation: