SOLUTION: Solve the problem.
Jan can run 5 miles per hour on level ground on a still day. One windy day, he runs 10 miles with the wind, and in the same amount of time runs 6 miles agai
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Jan can run 5 miles per hour on level ground on a still day. One windy day, he runs 10 miles with the wind, and in the same amount of time runs 6 miles agai
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Jan can run 5 miles per hour on level ground on a still day. One windy day, he runs 10 miles with the wind, and in the same amount of time runs 6 miles against the wind. What is the rate of the wind? This question is from textbook Algebra
You can put this solution on YOUR website! 10/(5+W)=6/(5-W) OR 30+6W=50-10W OR 16W=20 OR W=20/16 OR W=1.25 MPH
PROOF 10/(5+1.25)=6/(5-1.25) OR 10/6.25=6/3.75 37.5=37.5
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