SOLUTION: Working together, Fred and Jill can feed the chickens in 4 hours. Working alone, Jill can feed the chickens in 10 hours. How long would it take Fred to feed the chickens working b

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Working together, Fred and Jill can feed the chickens in 4 hours. Working alone, Jill can feed the chickens in 10 hours. How long would it take Fred to feed the chickens working b      Log On


   

Question 329023: Working together, Fred and Jill can feed the chickens in 4 hours. Working alone, Jill can feed the chickens in 10 hours. How long would it take Fred to feed the chickens working by himself?
Found 2 solutions by mananth, scott8148:
Answer by mananth(16946) About Me  (Show Source):
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Fred & jill together can do a job in 4 hours
so tthwy do 1/4 of the job in 1 hour
..
jill can do the job in 10 hours
she does 1/10 of the job in 1 hour
..
Fred will do 1/4 -1/10 of the job in 1 hour
LCD = 20
5-2 / 20 = 3/20
so fred can do the job alone in 20/3 hours
=6.66 hours

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
in 4 hr , Jill feeds 4/10 of the chickens ___ so Fred feeds 6/10

it would take Fred [4/(6/10)] hrs to feed all the chickens by himself