SOLUTION: please help I am so lost In 1992, the life expectancy of males in a certain country was 66.8 years. In 1996, it was 70.5 years. Let E represent the life expectancy in year t a

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Question 328863: please help I am so lost

In 1992, the life expectancy of males in a certain country was 66.8 years. In 1996, it was 70.5 years. Let E represent the life expectancy in year t and let t represent the number of years since 1992.
The linear function E(t) that fits the data is
Use the function to predict the life expectancy of males in 2005
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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In 1992, the life expectancy of males in a certain country was 66.8 years.
In 1996, it was 70.5 years. Let E represent the life expectancy in year t and
let t represent the number of years since 1992.
:
Find the slope
In 1992; x1=0 and y1=66.8
In 1996; x2=4 and y2=70.5
:
Find the slope (m) using the slope equation: m = %28y2-y1%29%2F%28x2-x1%29
m = %2870.5-66.8%29%2F%284+-+0%29%29 = %283.7%29%2F%284%29 = .925
:
Use the point/slope formula to write the equation; y - y1 = m(x - x1)
y - 66.8 = .925(x - 0)
y = .925x + 66.8
:
therefore:
The Linear function E(t) that fits the data is.
E(t)= .925t + 66.8
:
Use the function to predict the life expectancy of males in 2005
t = 2005 - 1992 = 13
E(13) = .925(13) + 66.8
E(13) = 12.025 + 66.8
E(13) = 78.8