SOLUTION: Three times the width of a certain rectangle exceeds twice its length by three inches, and four times its length is twelve more than its perimeter. Find the dimensions of the recta

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Three times the width of a certain rectangle exceeds twice its length by three inches, and four times its length is twelve more than its perimeter. Find the dimensions of the recta      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 328653: Three times the width of a certain rectangle exceeds twice its length by three inches, and four times its length is twelve more than its perimeter. Find the dimensions of the rectangle.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let length be x
width = y
3y=2x+3
3y-2x=3................1
4x-12 = 2(x+y)
4x-12=2x+2y
2x-2y=12
divide equation by 2
x-y=6.................2
mutiply equation 2 by 3 and add equation 1
3x-3y=18
3x-3y+3y-2x=18+3
x=21 inches which is the length
plug the value of x in equation 2
21-y=6
y=21-6
y= 15 inches the length