SOLUTION: please find the derivative of the function given by y=ln(sqr x) could you please show working

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Question 328648: please find the derivative of the function given by
y=ln(sqr x)
could you please show working
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
y=ln%28sqrt%28x%29%29
y=ln%28x%5E%281%2F2%29%29+
y=%281%2F2%29%2Alnx

All of this is still y. Notice that you did NOT take a derivative up to this point. NOW, take the derivative, and this becomes very simple.

y'=%281%2F2%29%2A%281%2Fx%29
y'=1%2F%282x%29

By the way, I don't have any sections of explanations on Calculus on my website, but I do have PRACTICE EXAMS with DETAILED SOLUTIONS posted for you.

To see this website, click on my tutor name "rapaljer" anywhere in algebra.com. Click on my website name that you will see there, and look on my Homepage for "Practice Tests." Choose "Calculus I" and look in "Exam 5 A" and "Exam 5 B" for Derivatives with Logarithms. See also "Concepts of Calulus" Exam 4. Take a look--it's all FREE!!!

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Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Dr. Robert J. Rapalje